Question

Show that for a body projected vertically up from the
ground, the distance travelled by it in the last second
of its upward motion is a constant independent of its
initial velocity.​

Answer 1

Answer:

say s is the distance covered by the object in upward direction.

s=ut-1/2  gt2 =ut-5t2

distance covered in (t-1) sec=s'=u(t-1)-5(t-1)2    

expand the prev identities.

so dist covered in last sec=s-s'=u-10t+5  ... (1)

 

now,v=0=u-10t

so  u=10t  put this in equ 1:

so dist in last sec=10t-10t+5=5=constant

Explanation: