Show that formation of Nacl
from sodium and chlorine
atom by transfer of electron
Answers
Answer:
The sodium atom transfers one electron to the chlorine atom,i n order to attain complete octet.With the transfer of the electron,however,they became electrically charged,a and combine into salts through the formation of ionic bonds. The sodium ion now has only ten electron but still has eleven protons.
Formation of NaCl:
1. Sodium has atomic number 11, shows the electronic configuration 2,8,1 to become complete by it's octet state, Sodium looses it's 1 electron and forms the sodium ion Na+ (2,8).
Sodium (Na) (2,8,1) -------------> Sodium ion (Na+) (2,8)
2. Chlorine has atomic number 17, shows electronic configuration 2,8,7. To become complete by it's octet state, it accepts 1 electron shared by Sodium and forms the Chlorine ion Cl- (2,8,8)
Chlorine (Cl) (2,8,7) --------------> Chloride ion (Cl-) (2,8,8)
3. Due to the opposite charges, there is a attraction between this two ions and one new chemical bond is formed.
Na₊ + Cl₋ -------------> NaCl
About Sodium Chloride:
Sodium Chloride is a common salt which is generally referred as "common salt" also. Sodium Chloride is colorless and crystalline ionic compound. By the further reactions on Sodium Chloride, Various salts like Na2Co3 and NaHCO3 are produced.
i) NaCl is generally salty in taste.
ii) It is Colourless , Neutral salt.
iii) There is no water of crystallization in it's crystalline structure.
iv) When the NaCl is heated at 800 degree Celsius, then it melts. This state of salt is called as "Fused state of salt".