show that how would you join three resistors of each resistance 6 ohm to that equivalent resistance of the combination is (1). 9 ohm (2).2 ohm
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Answer: R=R1+R2=9+9=18Ω 1/R'=1/R+1/R0=1/18+1/9=1+2/18=3/18 R'=18/3=6Ω
Explanation: p.s free fire is fun
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