Show that if the diagonals of a quadrilateral bisect
each other at right angles, then it is a rhombus
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ਕਿ ਗੁਪਤ ੂਗੁਵੀਕੂਦੀਵੂ੮ੁੂਲੂ੮੩ਤਡੈਹੀ੭ੂਵ੪ਬਕੂ੯੪ਲਗ੪ੂਗਨੂਰ੮ੂ੪
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Given:- Rhombus ABCD diagonal AC and BD which intersection at point O
Proof:- diagonal AC and BD bisect at 90°(right angle)
proof:- angle A+angle B
=180°( adjacent angle of rhombus is supplementary)
or 1/2 of A+1/2 of B= 90°
so, in triangle AOB angle A+ angle B= 90
so, angle O = 180°-90°
= 90°
so it is prooved that if the diagonal bisect at right angle than it is a rhombus
I hope it is helpful
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