Show that if the diagonals of a quadrilateral bisect each other at right angle
is a rhombus
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HERE IS YOUR ANSWER (. ❛ ᴗ ❛.)
Step-by-step explanation:
Take quadrilateral ABCD, AC and BD are diagonals which intersect at O. In AAOB and AAOD
DO = OBO is the midpoint
AO = AO Common side
ZAOB = ZAOD Right angle
So, AAOB AAOD
So, AB = AD
Similarly, AB BC = CD = AD can be proved which means that ABCD is a rhombus.
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