show that in a right angled triangle the hypotenuse in the longest side
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n a right angled triangle, the angle opposite To the hypotenuse is 90°, while other two angles are Always less than 90°. As you know that the side opposite to the largest angle is always the largest in a triangle.
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A right-angled triangle ABC in which ABC = 90°. We have to prove that AC is the longest side, i.e.,
(i) AC > AB
(ii) AC > BC
In ∆ ABC, WE HAVE
- ABC=90°
But ABC+BCA+CAB=180°.
=> 90°+BCA+CAB=180°.
=> BCA+CAB=180°-90°
=>BCA+CAB=90°.
=>BCA CAB are acute angles
=> BCA <90° and CAB<90°.
=> BCA<ABC and ABC>CAB
=> AC>AB AND AC>BC.
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