Question

show that in an isosceles triangle angle opposite to equal side are equal

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Answer 1

Step-by-step explanation:

Theorem 1: Angles opposite to the equal sides of an isosceles triangle are also equal. Proof: Consider an isosceles triangle ABC where AC = BC. We need to prove that the angles opposite to the sides AC and BC are equal, that is, ∠CAB = ∠CBA.

Answer 2

Answer:

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It is correct