show that in an isosceles triangle, angles are opposite to equal side are equal
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Draw a Triangle ABC
First,Consider a Perpendicular D from A at BC.
Now we have two Triangles -- ∆ABD,∆ACD
We need to prove that this two Triangles are congruent.
So,AB = AC (Given,since it's an isosceles triangle)
Angle ADB = Angle ADC (90° each)
AD = AD (Common)
Hence,∆ABD is congruent to ∆ACD by R.H.S rule.
Then,Angle B = Angle C (CPCT).
First,Consider a Perpendicular D from A at BC.
Now we have two Triangles -- ∆ABD,∆ACD
We need to prove that this two Triangles are congruent.
So,AB = AC (Given,since it's an isosceles triangle)
Angle ADB = Angle ADC (90° each)
AD = AD (Common)
Hence,∆ABD is congruent to ∆ACD by R.H.S rule.
Then,Angle B = Angle C (CPCT).
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