show that #Integrals
Attachments:
Answers
Answered by
1
1+cos2x
= 1 + cos²x - sin²x
= 1 + 2cos²x - 1
= 2cos²x
so
√(1+cos2x)dx = cosx√2 dx
integrate it to get
√2 sinx + C
= 1 + cos²x - sin²x
= 1 + 2cos²x - 1
= 2cos²x
so
√(1+cos2x)dx = cosx√2 dx
integrate it to get
√2 sinx + C
Answered by
1
Hi friend,
The formulas for cos2x are
1. Cos2x = cos²x-sin²x......(1)
2.cos2x = 2cos²x-1.....(2)
Take 1+cos2x
= 1+ cos²x-sin²x(from 1)
= 1+2cos²x-1
= 2cos²x
Taking square root on both the sides,
= √2 cosx
By doing integration,
= √2 sinx +c.
Hope this helped you a little!!!
The formulas for cos2x are
1. Cos2x = cos²x-sin²x......(1)
2.cos2x = 2cos²x-1.....(2)
Take 1+cos2x
= 1+ cos²x-sin²x(from 1)
= 1+2cos²x-1
= 2cos²x
Taking square root on both the sides,
= √2 cosx
By doing integration,
= √2 sinx +c.
Hope this helped you a little!!!
Similar questions