show that log xyz=logx+logy+logz.
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Answered by
14
RHS
log X + log Y + log Z
Now, taking log as common, we get
log ( X+Y+Z)
= LHS (Hence, Proved)
log X + log Y + log Z
Now, taking log as common, we get
log ( X+Y+Z)
= LHS (Hence, Proved)
rajlaxmidash201:
plz mark it as the best
you stolen the answer from shiva manoj[my brother]
but if the answer is same, what can i do !!!!
i don't no i can't pick as best
nonsense fellow
you only iam girl
Answered by
1
answer:
logabc=loga+logb+logc
logxyx=logc+logy+logz
I hope you like my answer
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