Question

show that log152/343+ 2log7/9- log1/7=log2.​

Answer 1

I think your question is incorrect, since the proof sits for 162 instead of 152. Assuming it is a typo, the proof is given below.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$log( \frac{152}{343} )+2log \frac{7}{9} - log( \frac{1}{7} ) = log(2)$

LHS:

$log(\frac{152}{343} \times \frac{49}{81}) - log( \frac{1}{7} )$

$log \frac{152}{567} - log( \frac{1}{7} )$

$log( \frac{152}{567} \div 7 ) = log(2)$

proved