show that log162/343+2log7/9-log1/7=log2
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Answer:
Log(162/343) + log(7/9)^2 - log(1/7)
=log[(162×7)/343] + log(49/81)
=log(162/49) +log(49/81)
=log[(162×49)/(49×81)]
=log2
Hence proved
Step-by-step explanation:
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