Show that m-1 is a factor of m²¹-1 and m²²-1.
Answers
Answered by
8
let
f(x)=m^{21} -1
and G(x)=m^22 -1
given
m-1 is a factor of given polynomial f(x) and G(x)
therfore 1 is the zeros of the given polynomial
if we put 1 in both polynomial then the polynomial qualto zero
hence m-1 is the factor of given polynomail
f(x)=m^{21} -1
and G(x)=m^22 -1
given
m-1 is a factor of given polynomial f(x) and G(x)
therfore 1 is the zeros of the given polynomial
if we put 1 in both polynomial then the polynomial qualto zero
hence m-1 is the factor of given polynomail
Answered by
5
Answer:
Step-by-step explanation:
Show that m-1 is a factor of m²¹-1 and m²²-1.
m²¹-1
if m-1 is factor then m=1
iff f(m) = 0
iff f(1) = 0
iff 1²¹ - 1 = 0
iff 1 - 1 =0
iff 0 = 0
which is true
so m-1 is a factor of m²¹-1
m²²-1
if m-1 is factor then m=1
iff f(m) = 0
iff f(1) = 0
iff 1²² - 1 = 0
iff 1 - 1 =0
iff 0 = 0
which is true
so m-1 is a factor of m²¹-1
Hence m-1 is a factor of m²¹-1 and m²²-1.
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