Question

Show that (m-1) is a factor of m2l 1 and m22 1.​

Answer 1

$\huge\red{ANSWER}$

Let f(m)=m

21

−1 and g(m)=m

22

−1.

The remainders when f(m) and g(m) are divided by m−1 are f(1) and g(1) respectively.

Now f(1)=0=g(1).

Now by factor theorem, as the remainders are zero, so the f(m) and g(m) are perfectly divisible by m−1.

So m−1 is a factor of the given expressions.

Answer 2

Answer:

Put m = 1 in the first polynomial

m (1) = (1)21 – 1

= 1 – 1

= 0

So m-1 is the factor of m21 -1

Put m = 1 in the second polynomial

m (1) = (1)22 – 1

= 1 – 1

= 0

So m-1 is the factor of m22 -1

Step-by-step explanation: