show that n²-n is divisible by 2
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Hey mate!
here's your answer:
Firstly, let n = 2q
n²-n = (2q)²-2q
= 2q(2q-1)
2m,when m=q(2q-1)
Which is divisible by 2
n = 2q+1
n²-n = (2q+1)(2q+1-1)
= 2q(2q+1)
2m, when m=q(2q+1)
Which is divisible by 2 hence ,n²-n is divisible by 2 for every positive integer n.
i hope it will be helpful to you
vaishnavi7474:
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