Question

show that no. 8n can never end with digit 0 for any natural no. n

Answer 1

8=2x2x2
a no 8n can only end with 0 if it is a multiple of 5.
8 is not
therefore 8n can never end with zero unless it is multiplied by 5 or a multiple of 5
i m not sure abt the answer

Answer 2

if 8n ends with zero then 8 will contain 5 or 0 in its prime factorisation.But 8n contains 2^3n and fundamental theorem of arithmetic gurantees that this prime factorisation is unique.Hence 8n never end with digit 0 for any natural number n.
Hope it hlps u.