Question

the sum of three consecutive multiple of 9 is 999 . find these multiple

Answer 1

hello users .....

given that :
the sum of three consecutive multiple of 9 is 999 .

we have to find the numbers .

solution:-

let. the first multiple of 9 = 9x
because these are consecutive .
then
2nd number = 9(x+1)
3rd number = 9(x+2)

Now,
According to question:
9x +9(x+1) + 9(x+2) = 999

=> 27x +27 = 999
=> 27x = 999-27 = 972
=> x = 36

hence;
1st number multiple of 9 = 9× 36 = 324
2nd number multiple of 9 = 9×37 = 333
3rd number multiple of 9 =9× 38 = 342

✡✡ hope it helps ✡✡

Answer 2

we find the multiple when firstly we start the solution let first digits x, x+1,x+2
x+(x+1)+(x+2)=999
x+x+1+x+2=999
3x+3=999
3x=999-3
3x=996
x=996/3
x=332
x+1=332+1=333
x+2=332+2=334
I hope u understand another you Chelk braily world