show that numbers 8^n can never end with digit o for any natural no. n
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let assume 8^n can end with zeroes
8^n=2^n×4^n
8^N=4^N××2^N
1 and 2 contradicts f.t.a
therefore 8^N cannot end with zero
8^n=2^n×4^n
8^N=4^N××2^N
1 and 2 contradicts f.t.a
therefore 8^N cannot end with zero
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if the the number 8^n,for any n were end with the digit zero then it would be divisible by 5
that, is the 0rime factorisation of 8^n would contain the prime 5. this is not possible because 8^n =(2)^n so the only prime in factorisation of8^n is 2. so,the uniqueness of the fundamentals Theorem of Arithmetic guarantee that there
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