Question

Show that of all rectangls inscribed in a given fixed circle, the squre has maximum area

Answer 1

Hope it helps

Area of Any rectangle (of which square is a special case) can be represented as are of two triangles in which the diagonal divides it. Here, since the area is right-angled, we can apply Pythagoras theorem.

a^2 + b^2 = c^2 ( a and b are the sides and c is the diagonal.)

Diagonals are nothing but chord in the circle. Since diameter is the longest chord, c^2 will be maximum when the diagonal passes through the centre of circle. This is the case when it is a square.

Since c^2 is max, c will be max. So a^2 + b^2 will be max. Therefore a and b will be max, therefore a x b will be max. Hence max area.

Answer 2

look at attachment then rectangle is square because all side are equal

i have proved it look at attachment