Question

show that one ampere is equivalent to a flow of 6.25×10^18 elementary charges per second

Answer 1

YES IT IS CORRECT

AS

I=Q/T


ALSO Q=ne


IF Q=6.25×10^18e


I=6.25×10^18×1.6×10^-19

I=10×10^-1

I=1AMPERE HENCE PROVED

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