Show that one and only one out of n , n+2 or n+4 is divisible by 3 , where n is any
positive integer.
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Answer:
case I: if n =3q
n is divisible by 3,
n+2 = 3q+2 is not divisible by 3.
n+4 = 3q+4 = 3(q+1)+1 is not divisible by 3.
case II: if n =3q+1
n = 3q+1 is not divisible by 3.
n+2 = 3q+1+2=3q+3 = 3(q+1) is divisible by 3.
n+4 = 3q+1+4 = 3q+5 = 3(q+1)+2 is not divisible by 3.
case III: if n = 3q+2
n =3q+2 is not divisible by 3.
n+2 = 3q+2+2 =3q+4 = 3(q+1)+1 is not divisible by 3.
n+4 = 3q+2+4 = 3q+6 = 3(q+2) is divisible by 3.
thus one and only one out of n , n+2, n+4 is divisible by 3.
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