Question

show that one and only out of n n+3 n+6or n+9 is divisible by 4

Answer 1

Hey dear!

Here is yr answer....

n+3 , n+6 , n+9

by taking n = even no. - 2


= n+3/4

= 2+3/4

= 5/4 ❎



= n+9/4

= 2+9/4

= 11/4 ❎


= n+6/4

= 2+6/4

= 8/4

= 2


Therefore, n+6 is divisible by 4


Hope it hlpz....

Answer 2

now divide n by 4 u get the answer n/4 so it is inappropriate

now n+3 it is also not divisible

n+6 can be divisible but remainder is 2

n+6 is also divisible but remainder 1
now let n = even no =2

now n/4=2/4=1/2 so wrong

now 2+3/4=5/4 still not divisible

now n+2=2+6=8/4 so its a correct one