Question

Show that one zero of 8x² – 30x + 27 is the square of the other​

Answer 1

Answer:

To show that the zero of the function is the square of the other, we factorize as follows:

8x^2-30x+27

factoring the above we get:

8x^2-12x-18x+27

factoring we obtain:

4x(2x-3)-9(2x-3)

=(2x-3)(4x-9)

from above roots we see that:

the zeros are:

x=3/2 and x=9/4

the second zero is the square of the first

Step-by-step explanation:

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Answer 2

Answer:

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