Show that only one of the number of n, n+2 and n +4 is divisble by 3.
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USING EUCLIDS DIVISION LEMMA,
a=bq+r
given,b=3
⇒a=3q+r
(r=0,1,2)
now,
When r=0,
n⇒a=3q+0——————————divisible
n+2⇒a=3q+2—————————not divisible
n+4⇒a=3q+4—————————not divisible
when r=1,
n⇒3q+1—————————not divisible
n+2⇒3q+3—————————divisible
n+4⇒3q+5—————————not divisible
when r=2,
n⇒3q+2—————————not divisible
n+2⇒3q+4—————————not divisible
n+4⇒3q+6—————————divisible
∴FROM 1,2,3 WE CAN SHOW THAT only one of the number of n, n+2 and n +4 is divisble by 3.
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