show that (p-1)is a factor of (p10-1) and also of (p11-1)
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Answered by
11
LET (P-1) IS THE FACTOR OF (P10-1) AND( P11-1)
P-1=0
P=1
{(1^10) -1}=1-1
=0
{(1^11) -1}=1-1
=0
HENCE PROVED.
Answered by
0
Answer:
1) f(x) = p10 – 1
g(x)=p-1
g(0)=p=1
f(1) = 1 – 1 = 0
2) p(x) = p11 – 1
g(1) = 1 -1 = 0
hope it helps
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