Question

show that (p-1)is a factor of (p10-1) and also of (p11-1)​

Answer 1

LET (P-1) IS THE FACTOR OF (P10-1) AND( P11-1)

P-1=0

P=1

{(1^10) -1}=1-1

=0

{(1^11) -1}=1-1

=0

HENCE PROVED.

Answer 2

Answer:

1) f(x) = p10 – 1

g(x)=p-1

g(0)=p=1

f(1) = 1 – 1 = 0

2) p(x) = p11 – 1

g(1) = 1 -1 = 0

hope it helps

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