show that p -1 is afactor of p10+p8+p6-p4-p2-1
Answers
Answered by
20
p-1=0
p=1
on putting an equation p =1
(1)×10+(1)×8+(1)×6-(1)×4-(1)×2-1
10+8+6-4-2-1 =18+6-6-1 =18-1 =17
no it is not factor
p=1
on putting an equation p =1
(1)×10+(1)×8+(1)×6-(1)×4-(1)×2-1
10+8+6-4-2-1 =18+6-6-1 =18-1 =17
no it is not factor
jassi48:
wrong answer bura mat manna
to answer kai hoga
answer hai 0
kon si class hai
bt this is not factor
for equation
class 5
Answered by
19
p-1=0
p=1
p10+p8+p6-p4-p2-1
=1x10+1x8+1x6-1x4-1×2-1
=10+8+6-4-2-1
=24-7
=17
therefore,p-1 is not a factor of p10+p8+p6-p4-p2-1
p=1
p10+p8+p6-p4-p2-1
=1x10+1x8+1x6-1x4-1×2-1
=10+8+6-4-2-1
=24-7
=17
therefore,p-1 is not a factor of p10+p8+p6-p4-p2-1
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