Question

show that p(X) =x cube -3x square +2x -6 has only one real zero

Answer 1

Answer:

IT'S X^3 -3X^2 +2X-6 = 0

X^2 (X-3)+2 (X-3) = 0

(X-3) (X^2+2) = 0

X=3. BUT X=-2ROOT (THAT'S NOT

POSSIBLE)

SO, X=3.

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Answer 2

Answer:

Step-by-step explanation:

Answer:

IT'S X^3 -3X^2 +2X-6 = 0

X^2 (X-3)+2 (X-3) = 0

(X-3) (X^2+2) = 0

X=3. BUT X=-2ROOT (THAT'S NOT

POSSIBLE)

SO, X=3.