Question

show that perimeter of a triangle is greater than twice the median​

Answer 1

Answer:

HI MATE !

We know that the sum of any two sides of a triangle is greater than twice the median drawn to the third side. ∴ (AB+BC+AC)>(AD+BE+CF). Hence, the perimeter of a triangle is greater than the sum of its three medians.

Hope my answer helps you Dear.. ✌️❤️

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Answer 2

hope this will be helpful to you