Math, asked by sandhyakumari89, 4 months ago

. Show that points A(7, 5), B(2, 3) and C(6, -7) are the vertices of a right triangle. Also find it's area *


Answers

Answered by prathapreddyramiredd
1

Step-by-step explanation:

Given points are

A(7,5),B(2,3),C(6,-7)

By distance formula

AB =(3-5)^2+(2-7)^2

=(-2)^2+(-5)^2

=4+25

=29

BC =(-7-3)^2+(6-2)^2

=100+16

=116

AC = (-7-5)^2+(6-7)^2

=145

Pythagoras Theron

AC^2=BC^2+AB^2

(145)^2= (116)^2+(29)^2

145=116+29

145=145

LHS = RHS

therefore the given vertices are if right angled triangle

Similar questions