show that polynomial x²-2x+5 has no real zeros
Answers
Answered by
77
Bonjour!
Given polynomial :- x² - 2x + 5
a = 1
b = -2
c = 5
When discriminant is less than 0 then we say the polynomial have no real zero.
(D<0)
=> D = b² - 4ac
=> D = (-2)² - 4(1)(5)
=> D = 4 - 20
=> D = -16
As, we can see that discriminant(D) is less than zero.
So, by this we can say that polynomial x²- 2x+5 has no real zeros.
Hope this helps...:)
Given polynomial :- x² - 2x + 5
a = 1
b = -2
c = 5
When discriminant is less than 0 then we say the polynomial have no real zero.
(D<0)
=> D = b² - 4ac
=> D = (-2)² - 4(1)(5)
=> D = 4 - 20
=> D = -16
As, we can see that discriminant(D) is less than zero.
So, by this we can say that polynomial x²- 2x+5 has no real zeros.
Hope this helps...:)
Answered by
1
Hii. ...friend
The answer is here,
To find nature of roots.we have to find the discriminate .
=> 4-20.
=> -16.
Here, Discriminate is less than zero. So, The polynomial has not real roots.
:-)Hope it helps u.
The answer is here,
To find nature of roots.we have to find the discriminate .
=> 4-20.
=> -16.
Here, Discriminate is less than zero. So, The polynomial has not real roots.
:-)Hope it helps u.
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