Show that polynomial x2 +6x+12 has no real factors
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X² + 6X + 12
Here,
A = 1 , B = 6 and C = 12
Therefore,
Discriminant (D) = B²-4AC
=> (6)² - 4 × 1 × 12
=> 36 - 48
=> -12
Hence,
The given equation has No Real roots because Discriminant of the equation is smaller than 0.
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
X² + 6X + 12
Here,
A = 1 , B = 6 and C = 12
Therefore,
Discriminant (D) = B²-4AC
=> (6)² - 4 × 1 × 12
=> 36 - 48
=> -12
Hence,
The given equation has No Real roots because Discriminant of the equation is smaller than 0.
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
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