show that root 7- 3 is irrational
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Here we will prove it by contradiction,i.e assume that √7 -3 is a rational and show that assumption is wrong.
SOLUTION :
Let us assume that √7 - 3 is rational.Then it will be of the form a/b ,where a,b are coprime Integers and b≠0.
√7 - 3 = a/b
On rearranging ,
√7= a/b + 3
Since,a/b and 3 are rational. So their sum will be rational.
Therefore √7 is rational number.
But we know that, √7 is irrational number.
Thus , there is a contradiction. Hence Our assumption is wrong that √7 - 3 is rational.
Hence,√7 - 3 is irrational
HOPE THIS WILL HELP YOU….
SOLUTION :
Let us assume that √7 - 3 is rational.Then it will be of the form a/b ,where a,b are coprime Integers and b≠0.
√7 - 3 = a/b
On rearranging ,
√7= a/b + 3
Since,a/b and 3 are rational. So their sum will be rational.
Therefore √7 is rational number.
But we know that, √7 is irrational number.
Thus , there is a contradiction. Hence Our assumption is wrong that √7 - 3 is rational.
Hence,√7 - 3 is irrational
HOPE THIS WILL HELP YOU….
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