Question

show that: sec40°sin50°+cos50°cosec40°=2

Answer 1

=> sec40° sin50° + cos50° cosec40°

=> sec40° sin(90 - 40) + cos50° cosec(90 - 50)


=> sec40° cos40° + cos50° sec50°

$=> \sec(40) \times \frac{1}{ \sec(40) } + \cos( 50) \times \frac{1}{ \cos(50) } \\ \\ \\ \\ \\ = > 1 + 1 \\ \\ \\ = > 2$


Hence, proved.