Question

Show that sin^2 30+cos^2 60+tan^2 45 = -1/2

Answer 1

Step-by-step explanation:

We have,

2 (cos

2

45

∘

+tan

2

60

∘

) - 6 (sin

2

45

∘

−tan

2

30

∘

)

=2[(

2

1

)

2

+(

3

)

2

]−6[(

2

1

)

2

−(

3

1

)

2

]

=2(

2

1

+3)−6(

2

1

−

3

1

)=2(

2

1+6

)−6(

6

3−2

) = 7−1=6