Question

Show that sin^2(45)-sin^2(15) =root 3/4

Answer 1

Answer:

$clearly \: \\ { \sin(45) }^{2} - { \sin(15) }^{2} = \sqrt{ \frac{3}{4} } \\ { \ - sin(15) }^{2} = \sqrt{ \frac{3}{4} } - { \sin(45) }^{2} \\ { \sin(15) }^{2} = \frac{1}{ { \sqrt{2} }^{2} } - \sqrt{ \frac{3}{4} } \\ { \sin(15) }^{2} = \frac{1}{2} - \ \frac{ \sqrt{3} }{2} \\ \sin(15) = \sqrt{ \frac{1 - \sqrt{3} }{2} }$

Answer 2

Step-by-step explanation:

$\\ \\ \\ \\ \\ \\ \\ \ \sin^{2} 45 - \sin^{2} 15 = \frac{ \sqrt{3} }{4 \\ \\ }$