Question

Show that ( sin 35 / cos 55) square - 2 cos 60 = 1/2​

Answer 1

Step-by-step explanation:

(sin35/cos55)²+(cos55/sin35)²-2cos60

=[cos(90-35)/cos55]²+[cos55cos(90-35)]²-2cos60

=(cos55/cos 55)²+(cos55/cos 55)²-2cos60

=1+1-2×1\2

=1+1-1

=1

Hope it helps you

Answer 2

The equation is not correct.

Step-by-step explanation:

Show that : $(\frac{\sin 35}{\cos 55})^2-2 \cos 60=\frac{1}{2}$

Solution :

Taking LHS,

$LHS=(\frac{\sin 35}{\cos 55})^2-2 \cos 60$

Applying trigonometric property, $\sin (90-\theta)=\cos \theta$

Re-write the expression as,

$LHS=(\frac{\sin (90-55)}{\cos 55})^2-2 \cos 60$

$LHS=(\frac{\cos 55}{\cos 55})^2-2 \cos 60$

Substitute, $\cos 60=\frac{1}{2}$

$LHS=(1)^2-2(\frac{1}{2})$

$LHS=1-1$

$LHS=0$

$LHS\neq RHS$

The equation is not correct.

#Learn more

Let us show that cos 55° cos 45°— sin 55° sin 35° = 0 .​

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