show that
sin 42° sec48°+cos42°cosec48°=2
jashbant:
sin42×cosec42+cos42×sec42 .then1+1=2
thanks
Answers
Answered by
9
ans cos48 sec48+ sin 48 cosec48
cos 48 1/cos48+ sin 48 1/sin48
cos and sin cancels so 1+1=2
hence proved
cos 48 1/cos48+ sin 48 1/sin48
cos and sin cancels so 1+1=2
hence proved
thanks but i think u have input wrong q .The q was sin42° sec48°+cos42°cosec48°=2
i only change sec48 and cosec48 which was necessary in the second step.please read the q. thoroughly
ok
Answered by
17
sin 42.cosec ( 90-48) +cos42.sec(90-48)=2
sin42.cosec42+ cos42.sec42=2
sin42 ×1/sin42 + cos 42 × 1/cos 42=2
1×1 + 1×1 = 2
1+1=2
2=2
sin42.cosec42+ cos42.sec42=2
sin42 ×1/sin42 + cos 42 × 1/cos 42=2
1×1 + 1×1 = 2
1+1=2
2=2
thank you
mention not
its ok
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