solve the problem.
fast
Attachments:
Answers
Answered by
0
diameter of well =4.20m
radius of well,r=4.20m/2=2.10m
depth of well ,h=10m
inner area of well=curved surface area of well +pi r^2
=2*22/7*2.10*10+22/7*2.10*2.10
solve it you will get area.
cost of plastering=surface area*52
solve it you will get the cost
radius of well,r=4.20m/2=2.10m
depth of well ,h=10m
inner area of well=curved surface area of well +pi r^2
=2*22/7*2.10*10+22/7*2.10*2.10
solve it you will get area.
cost of plastering=surface area*52
solve it you will get the cost
Physicist182:
Mark me brainliest please
Answered by
0
Above is your solution.. It's from digest.. Please make my answer as Brainliest
Attachments:
Similar questions