Question

show that sin (50°+thita) - cos (40°- THITA)=0

need full explanation?

Answer 1

hope this will help you.. :-)

Answer 2

Here your answer goes

Step :- 1

Given ,

$Sin ( 50 + theta ) - (Cos40 - theta )$

Sin 50° can be written as 90° - 45°

⇒ Sin (90 - 40 + theta ) - Cos ( 40 - theta )

Step :- 2

$sin[90-(40-theta)]- cos(40-theta)$

⇒ $cos(40-theta)-cos(40-theta)$

∴  sin ( 90 - theta ) = Cos theta

⇒ 0

Therefore ,  Sin ( 50 + theta ) - Cos( 40 - theta ) = 0

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