Question

show that sin 70×cos 10- cos 70× sin 10

Answer 1

Answer:

$\red {Sin\:70\degree \times cos \:10\degree - cos\:70\degree \times sin \:10\degree}\green {=\frac{\sqrt{3}}{2}}$

Step-by-step explanation:

$Sin\:70\degree \times cos \:10\degree - cos\:70\degree \times sin \:10\degree$

$= sin ( 70 - 10)$

$\boxed { \pink { sin AcosB - SinBcosA = sin(A-B)}}$

$= sin 60\degree \\= \frac{\sqrt{3}}{2}$

Therefore.,

$\red {Sin\:70\degree \times cos \:10\degree - cos\:70\degree \times sin \:10\degree}\green {=\frac{\sqrt{3}}{2}}$

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