Math, asked by Srivyshnavnch, 10 months ago

Show that (sin theta + cos theta)2 + (sin theta -cos theta)2 = 2.

Answers

Answered by hancyamit2003

1

Answer:

Step-by-step explanation:

LHS=( Sin Q+cos Q)^2+(sinQ-CosQ)^2

=(Sin^2Q+cos^2Q+2sinQcosQ)+(sin^2Q+cos^2Q-2sinQcosQ)

=1+2sinQcosQ+1-2sinQcosQ

=2

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