Show that (sin theta + cos theta)2 + (sin theta -cos theta)2 = 2.
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Answer:
Step-by-step explanation:
LHS=( Sin Q+cos Q)^2+(sinQ-CosQ)^2
=(Sin^2Q+cos^2Q+2sinQcosQ)+(sin^2Q+cos^2Q-2sinQcosQ)
=1+2sinQcosQ+1-2sinQcosQ
=2
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