Question

show that (sin0+cosπ÷6)(sinπ÷6+tanπ÷4)÷(tanπ÷6+cosπ÷3)(secπ÷3–cosecπ÷2)=9/8​

Answer 1

Answer :

$(0 + \frac{ \sqrt{3} }{2} )( \frac{1}{2} )( \frac{1}{ \sqrt{3} } + \frac{1}{ \sqrt{3} } )(2 - 1) \\ \\ = = > \: \frac{ \sqrt{3} }{3} \times \frac{3}{2} \times \frac{2}{ \sqrt{3} } \\ \\ = = > \: \frac{3}{2}$

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