show that sin35.sin55-cos55.cos35=0
Answers
Answered by
3
Here.
Sin(35°)=cos(90-55)=cos(35°)
and Sin(55°)=cos(90-55)=cos(35°)
Substituting this in the Given equation...
→cos(35°).cos(55°)-cos(55°).cos(35°)
which is =>
cos(35°).cos(55°)-cos(35°).cos(55°)=0
Hope it helps.
Regards,
Leukonov.
Sin(35°)=cos(90-55)=cos(35°)
and Sin(55°)=cos(90-55)=cos(35°)
Substituting this in the Given equation...
→cos(35°).cos(55°)-cos(55°).cos(35°)
which is =>
cos(35°).cos(55°)-cos(35°).cos(55°)=0
Hope it helps.
Regards,
Leukonov.
Similar questions