Show that sum of interior angle of triangle is 180degree
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We know that, alternate interior angles are of equal magnitude.
This'll help us get the answer.
Let us assume a triangle ABC. Now we have to substitute the angles.
∠PAB + ∠BAC + ∠CAQ = 180°.
where PQ line parallel to side BC touching vertex A.
∠PAB = ∠ABC & ∠CAQ = ∠ACB [ BECAUSE alternate interior angles are congruent..]
Hence we get, ∠ABC + ∠BAC + ∠ACB = 180° [Proved]
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the sum of all the angles in an interior triangle is 180°
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