Question

show that sum of two sides of a triangle is greater than third side

Answer 1

as we know that , 3 , 4, 5 are the triplets of right angled triangle as it is proved below ,

here H = 5 , P = 4 ,B =3

(H)^2 = (P)2 + (B)^2

(5)^2 = (4)^2 + (3)^2

25 = 25

L.H.S = R.H.S

but if we add two sides of this triangle the obtained length will be more than the third side of the right angled triangle.

5 < (3 + 4)

5 < 7
similary if we add 5 and 3 then

(5 + 3 ) > 4

and similarly if we add ,5 and 4

( 5 + 4 ) > 3

it shows that the sum of two sides of triangle always be greater than the third side of the triangle.

◆hope it helps◆