show that tan 48°tan23°tan42°tan67°=1
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L.H.S
◆tan48°tan42° tan23°tan67°
=tan (90 - 42) tan42° tan(90 -67) tan 67°
= cot42° tan42° cot67°tan67°
= (1/tan42°× tan42)° (cot67° ×1/cot67° )
= 1×1 = 1 ,R.H.S
◆hope it helps ◆
◆tan48°tan42° tan23°tan67°
=tan (90 - 42) tan42° tan(90 -67) tan 67°
= cot42° tan42° cot67°tan67°
= (1/tan42°× tan42)° (cot67° ×1/cot67° )
= 1×1 = 1 ,R.H.S
◆hope it helps ◆
lalith482:
How( 90_42)???
because 90 -42 = 48
if we subtract it ,it will be the same answer
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Ur ansr mate...
Hope it helps you. .
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