Question

show that tan square theta-1 by cos square theta=-1
please tell mee answer fast

Answer 1

${tan}^{2} - \frac{1}{ {cos}^{2} }$

$= > {tan}^{2} - {sec}^{2}$

Since,

Sec^2-tan^2 = 1



=> -1 = RHS

Thus,It is proved that

${tan}^{2} - \frac{1}{ {cos}^{2} } = - 1$