Math, asked by american1, 7 months ago

Show that
tan48°tan23°tan42°tan67°=1.

Give only relevant answers. ​

Answers

Answered by tarneeverma93
1

Answer:

L.H.S. tan48 tan42 tan67 tan23

= tan48 tan (90-48) tan67 tan(90-67)

=( tan48 cot48) ( tan67 cot 67)

= tan48 1/tan48 tan67 1/tan67

= 1×1

= 1

R.H.S

Similar questions