Question

show that tanA ×SinA+cosA=secantA
please answer me fastly

Answer 1

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Answer 2

Let us take the LHS part ...
TanA×SinA + CosA

=
$\frac{sina \: \times sina}{cosa \: } + cosa \\ = \frac{ {sin}^{2} + cosa \times cosa }{cosa} \\ = \frac{ {sina}^{2} + {cosa}^{2} }{cosa} \\ = \frac{1}{cosa} \\ = seca$
Hope it helps...
Regards,
Leukonov.