Question

show that tangents drawn at the end points of a diameter of a circle are parallel.​

Answer 1

Draw a line bisecting two parallel tangents which move from the center of circle . Then name it . Then you can see the alternate interior angle property and 90 degree . Apply it . Then you prove it

Answer 2

Let AB be a diameter of the circle. Two tangents PQ and RS are drawn at points A and B respectively.

Radius drawn to these tangents will be perpendicular to the tangents.

Thus, OA ⊥ RS and OB ⊥ PQ

∠OAR = 90º

∠OAS = 90º

∠OBP = 90º

∠OBQ = 90º

It can be observed that

∠OAR = ∠OBQ (Alternate interior angles)

∠OAS = ∠OBP (Alternate interior angles)

Since alternate interior angles are equal, lines PQ and RS will be parallel .